2.5 KiB
2.5 KiB
title | description | menu | weight | flux/v0/tags | introduced | |||||||||
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date.sub() function | `date.sub()` subtracts a duration from a time value and returns the resulting time value. |
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101 |
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0.162.0 |
date.sub()
subtracts a duration from a time value and returns the resulting time value.
Function type signature
(d: duration, from: A, ?location: {zone: string, offset: duration}) => time where A: Timeable
{{% caption %}} For more information, see Function type signatures. {{% /caption %}}
Parameters
from
({{< req >}}) Time to subtract the duration from.
Use an absolute time or a relative duration.
Durations are relative to now()
.
d
({{< req >}}) Duration to subtract.
location
Location to use for the time value.
Examples
- Subtract six hours from a timestamp
- Subtract six hours from a relative duration
- Subtract two days from one hour ago
Subtract six hours from a timestamp
import "date"
date.sub(from: 2019-09-16T12:00:00Z, d: 6h)// Returns 2019-09-16T06:00:00.000000000Z
Subtract six hours from a relative duration
import "date"
option now = () => 2022-01-01T12:00:00Z
date.sub(d: 6h, from: -3h)// Returns 2022-01-01T03:00:00.000000000Z
Subtract two days from one hour ago
A time may be represented as either an explicit timestamp
or as a relative time from the current now
time. sub can
support either type of value.
import "date"
option now = () => 2021-12-10T16:27:40Z
date.sub(from: -1h, d: 2d)// Returns 2021-12-08T15:27:40Z