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[zh] fix: minimum feasible nodes 50->100 

Corresponds to #46994.
pull/47032/head
Shunsuke Ise 2024-06-29 21:03:46 +09:00
parent edd590e063
commit c64996e534
1 changed files with 4 additions and 4 deletions
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8
content/zh-cn/docs/concepts/scheduling-eviction/scheduler-perf-tuning.md
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@ -191,13 +191,13 @@ percentageOfNodesToScore: 50
<!-- <!--
`percentageOfNodesToScore` must be a value between 1 and 100 with the default `percentageOfNodesToScore` must be a value between 1 and 100 with the default
value being calculated based on the cluster size. There is also a hardcoded value being calculated based on the cluster size. There is also a hardcoded
minimum value of 50 nodes. minimum value of 100 nodes.
--> -->
`percentageOfNodesToScore` 的值必须在 1 到 100 之间，而且其默认值是通过集群的规模计算得来的。 `percentageOfNodesToScore` 的值必须在 1 到 100 之间，而且其默认值是通过集群的规模计算得来的。
另外，还有一个 50 个 Node 的最小值是硬编码在程序中。 另外，还有一个 100 个 Node 的最小值是硬编码在程序中。
<!-- <!--
{{< note >}} In clusters with less than 50 feasible nodes, the scheduler still {{< note >}} In clusters with less than 100 feasible nodes, the scheduler still
checks all the nodes because there are not enough feasible nodes to stop checks all the nodes because there are not enough feasible nodes to stop
the scheduler's search early. the scheduler's search early.
@ -210,7 +210,7 @@ scheduler's performance significantly.
{{< /note >}} {{< /note >}}
--> -->
{{< note >}} {{< note >}}
当集群中的可调度节点少于 50 个时，调度器仍然会去检查所有的 Node， 当集群中的可调度节点少于 100 个时，调度器仍然会去检查所有的 Node，
因为可调度节点太少，不足以停止调度器最初的过滤选择。 因为可调度节点太少，不足以停止调度器最初的过滤选择。
同理，在小规模集群中，如果你将 `percentageOfNodesToScore` 同理，在小规模集群中，如果你将 `percentageOfNodesToScore`