[audio] audio servlet: don't change map while used by interation (#801)
We should not remove entries (so keys) from the map while we are using the key set (a view) of that map (see JavaDoc: otherwise "results of the iteration undefined"). Signed-off-by: Markus Rathgeb <maggu2810@gmail.com>pull/796/head
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81423aa22e
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d19ee33be9
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@ -15,7 +15,10 @@ package org.eclipse.smarthome.core.audio.internal;
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import java.io.IOException;
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import java.io.InputStream;
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import java.util.Collections;
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import java.util.LinkedList;
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import java.util.List;
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import java.util.Map;
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import java.util.Map.Entry;
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import java.util.UUID;
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import java.util.concurrent.ConcurrentHashMap;
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import java.util.concurrent.TimeUnit;
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@ -143,16 +146,20 @@ public class AudioServlet extends SmartHomeServlet implements AudioHTTPServer {
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}
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private synchronized void removeTimedOutStreams() {
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for (String streamId : multiTimeStreams.keySet()) {
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if (streamTimeouts.get(streamId) < System.nanoTime()) {
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// the stream has expired, we need to remove it!
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FixedLengthAudioStream stream = multiTimeStreams.remove(streamId);
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streamTimeouts.remove(streamId);
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IOUtils.closeQuietly(stream);
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stream = null;
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logger.debug("Removed timed out stream {}", streamId);
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// Build list of expired streams.
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final List<String> toRemove = new LinkedList<>();
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for (Entry<String, Long> entry : streamTimeouts.entrySet()) {
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if (entry.getValue() < System.nanoTime()) {
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toRemove.add(entry.getKey());
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}
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}
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toRemove.forEach(streamId -> {
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// the stream has expired, we need to remove it!
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final FixedLengthAudioStream stream = multiTimeStreams.remove(streamId);
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streamTimeouts.remove(streamId);
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IOUtils.closeQuietly(stream);
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logger.debug("Removed timed out stream {}", streamId);
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});
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}
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@Override
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