98 lines
2.7 KiB
Python
98 lines
2.7 KiB
Python
# -*- coding: utf-8 -*-
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#
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# Copyright 2017 Mycroft AI Inc.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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from mycroft.util.lang.format_common import convert_to_mixed_fraction
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FRACTION_STRING_PT = {
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2: 'meio',
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3: u'terço',
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4: 'quarto',
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5: 'quinto',
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6: 'sexto',
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7: u'sétimo',
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8: 'oitavo',
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9: 'nono',
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10: u'décimo',
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11: 'onze avos',
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12: 'doze avos',
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13: 'treze avos',
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14: 'catorze avos',
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15: 'quinze avos',
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16: 'dezasseis avos',
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17: 'dezassete avos',
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18: 'dezoito avos',
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19: 'dezanove avos',
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20: u'vigésimo',
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30: u'trigésimo',
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100: u'centésimo',
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1000: u'milésimo'
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}
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def nice_number_pt(number, speech, denominators):
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""" Portuguese helper for nice_number
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This function formats a float to human understandable functions. Like
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4.5 becomes "4 e meio" for speech and "4 1/2" for text
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Args:
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number (int or float): the float to format
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speech (bool): format for speech (True) or display (False)
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denominators (iter of ints): denominators to use, default [1 .. 20]
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Returns:
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(str): The formatted string.
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"""
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result = convert_to_mixed_fraction(number, denominators)
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if not result:
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# Give up, just represent as a 3 decimal number
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return str(round(number, 3))
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whole, num, den = result
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if not speech:
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if num == 0:
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# TODO: Number grouping? E.g. "1,000,000"
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return str(whole)
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else:
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return '{} {}/{}'.format(whole, num, den)
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if num == 0:
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return str(whole)
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# denominador
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den_str = FRACTION_STRING_PT[den]
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# fracções
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if whole == 0:
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if num == 1:
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# um décimo
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return_string = 'um {}'.format(den_str)
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else:
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# três meio
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return_string = '{} {}'.format(num, den_str)
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# inteiros >10
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elif num == 1:
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# trinta e um
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return_string = '{} e {}'.format(whole, den_str)
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# inteiros >10 com fracções
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else:
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# vinte e 3 décimo
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return_string = '{} e {} {}'.format(whole, num, den_str)
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# plural
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if num > 1:
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return_string += 's'
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return return_string
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